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At what distance from a 1.00*10^-5 C charge will the electric potential be 10000 V? (Unit = m)​

User FBH
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2 Answers

3 votes

Answer:

9.0

Step-by-step explanation:

User Mernst
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3.0k points
3 votes

Answer:

9.0 m

Step-by-step explanation:

Applying

V = kq/r......................... Equation 1

Where V = Electric potential, q = charge, r = distance, k = Coulomb's constant.

make r the subject of the equation

r = kq/V................... Equation 2

From the question,

Given: q = 1.00×10⁻⁵ C, V = 10000 V

Constant: k = 9.0×10⁹ N⋅m²/C²

Substitute these values into equation 2

r = (9.0×10⁹×1.00×10⁻⁵)/10000

r = 9.0 m

User Davidnr
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2.9k points