Question

Question 1
Let f(x)=x3−4x2+6 and g(x)=f(−x)+4. Write a rule for g.

Answer 1

g(x)= - x3−4x²+10

Explanation:

hello

Let f(x)=x3−4x2+6 so g(x)=f(−x)+4.

g(x)=(-x)3−4(-x)²+6+4

g(x)= - x3−4x²+10 is a rule for g be cause (-x)3=- x3 and (-x)²=x²