157 views
1 vote
2x²-5x+2=0 solve for x​

User Chrispy
by
5.2k points

1 Answer

3 votes


{ \huge {\underline {\underline {\mathfrak {\purple{Answer}}}}}}


\longmapsto{2 {x}^(2) - 5x + 2}


\longmapsto{2 {x}^(2) - 4x - x + 2}


\longmapsto{2x(x - 2) - 1(x - 2)}


\longmapsto{(2x - 1)(x - 2)}


\boxed{ \huge x = \huge(1)/(2) \: or \: 2}

User Ahmed Kato
by
4.3k points