Question

The play space is 10 ft to 12 ft. Logan is getting a second dog and wants to increase the length of the play space by 3 feet and the width by 3 feet. What will be the difference in the area, in square feet, between the original play space and the new play space

Answer 1

Answer:
`75\ ft^2`

Explanation:

Given

The dimension of playspace is
`10\ ft* 12\ ft`

If the length and width is increased by 3 ft

New length is
`13\ ft`

New width is
`15\ ft`

So, the dimension becomes
`13\ ft* 15\ ft`

The difference between the areas of the playspace is

`\Rightarrow 13* 15-10* 12\\\Rightarrow 195-120=75\ ft^2`