Question

❤️ i need this last question

Answer 1

Answer:
`10\left(\cos90^(\circ)+i\sin90^(\circ)\right)`

Explanation:

Given

The complex number is
`z_1=0+10i`

Complex number in polar form is given by

`z=r\left(\cos \theta +i\sin \theta\right)`

Compare it with the given complex number

`r=10` and
`\sin \theta=1` which implies
`\theta` must be
`90^(\circ)`

So, in the polar form, it is

`z_1=10\left(\cos90^(\circ)+i\sin90^(\circ)\right)\\z_1=10e^{i(\pi)/(2)}`