Question

An electron and a proton are separated by 1.50 × 10^-10 m. If they are released, which one will accelerate at a greater rate, and what is the magnitude of that initial acceleration? (m(electron) =9.1x10 -31kg, m(proton) =1.67x 10-27kg )

Answer 1

Step-by-step explanation:

The electron with a smaller mass will accelerate faster than the proton as the force is the same.

Charge on electron = Charge on proton = 1.6*10^-19C

Distance between the two electrons = 1.5*10^-10m

The Electric force between two electrons is given by :

k*Q1*Q2/d^2, where k is the Coulombic constant = 9*10^9

= (9*10^9)*1.6*10^-19*1.6*10^-19/(1.5*10^-10)^2

= 1.024*10^-8N

Electron acceleration = Force/mass

= 1.024*10^-8/9.1x10^-31

= 1.125*10^22 m/s^2

Answer 2

Step-by-step explanation:

electron will accelerate faster cuz' its lighter

charge on electron n proton = 1.6*10^-19C

coulombic force bet electron n proton

= k*q^2/d^2 where k is the Coulombic constant = 9*10^9

= (9*10^9)*(1.6*10^-19)^2/(1.5*10^-10)^2

= 1.02*10^(-8)N

force = mass*acceleration

e- mass: 9.1*10^(-31)

acceleration = 1.02*10^(-8)/(9.1*10^(-31))

= 1.12*10^(22) m/s^2