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Tan^2A -sin^2A=sin^2a Tan^2A​
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Tan^2A -sin^2A=sin^2a Tan^2A​

User Andrii Kovalenko
by
3.9k points

1 Answer

5 votes

Answer:

see explanation

Explanation:

Using the identity

sin²A = 1 - cos²A , tanA =
(sinA)/(cosA)

Consider the left side

tan²A - sin²A

=
(sin^2A)/(cos^2A) - sin²A


(sin^2A-sin^2Acos^2A)/(cos^2A)

=
(sin^2A(1-cos^2A))/(cos^2A)

=
(sin^2A.sin^2A)/(cos^2A)

= sin²A ×
(sin^2A)/(cos^2A)

= sin²A . tan²A

= right side , thus verified

User Kurikintoki
by
4.6k points
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