Question

Solve
f(x)=2x^2+6, fund the value if f(x+3)​

Answer 1

F=2x^2+24

Explanation:

F (x+3)=2x^2+6

F=2(x+3)^2+6

F=2(X^2+9)+6

F=2x^2+18+6

F=2x^2+24