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Solve f(x)=2x^2+6, fund the value if f(x+3)​
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3 votes
Solve
f(x)=2x^2+6, fund the value if f(x+3)​

User Vadym Chumel
by
4.6k points

1 Answer

3 votes

Answer:

F=2x^2+24

Explanation:

F (x+3)=2x^2+6

F=2(x+3)^2+6

F=2(X^2+9)+6

F=2x^2+18+6

F=2x^2+24

User Thomas Anthony
by
4.8k points
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