Question

How many grams of potassium carbonate are needed to make 300ml of a 4.5M solution?

Answer 1

186.3g

Step-by-step explanation:

4.5moles of K₂CO₃ is in 1000ml

? moles of K₂CO₃ is in 300 ml

(4.5 × 300)/ 1000 = 1.35 moles of K₂CO₃

1 mole of K₂CO₃ = (39 × 2) + 12 + (16 × 3) = 78 + 12 + 48 = 138g

1.35 moles of K₂CO₃ = ?

= (1.35 × 138)/1 = 186.3g