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Calculate the pH of the solution: [OH-] = 1x10^-11M a.11.0 b.12.0 c.2.7 d.3.0
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Calculate the pH of the solution:

[OH-] = 1x10^-11M
a.11.0
b.12.0
c.2.7
d.3.0

User Speerian
by
6.7k points

1 Answer

6 votes

p [OH-] = -log[OH-]= -log ( 1x10^-11M) = 11

we know that

p[OH-] + p[H+] = 14

so p[H+] = 14- p[OH-] = 14- 11 = 3

pH = 3, answer

User Paulo Moura
by
6.5k points
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