Answer:
The frequency is 0.25Hz and the period is 4s
Step-by-step explanation:
To solve this we can use the formula:
, where f=frequency, v=velocity and lambda = wavelength.
In the question, we are given the information that the velocity of the wave is 6.5m/s and the wavelength is 26 meters long. By putting these values into the formula, we can find the frequency:
![f=(6.5)/(26) \\f= 0.25Hz](https://img.qammunity.org/2022/formulas/physics/high-school/v92dblxu82fwlk3q83ylse4ytcfkt2e9ei.png)
Period is the inverse of frequency:
![T=(1)/(f)](https://img.qammunity.org/2022/formulas/mathematics/college/khp6tkjhdea61le0mlsvoyqelu74c0x1rd.png)
Therefore the period is:
![T = (1)/(0.25) \\T = 4s](https://img.qammunity.org/2022/formulas/physics/high-school/2p1ct3t1hzecvg6n32k2p46qiime7p1lka.png)
Hope this helped!