Final answer:
To calculate the volume of a solution with 5.120 moles of Li2SO3 and a molarity of 6.750 M, divide the moles by the molarity, giving a volume of approximately 0.7585 liters.
Step-by-step explanation:
The student has posed a question concerning the calculation of the volume of a solution using its molarity and the amount of moles of solute present. To find the volume (in liters), we use the formula:
Volume (L) = Moles of solute (mol) ÷ Molarity (M)
Given the moles of solute as 5.120 moles and the molarity as 6.750 M, we can rearrange the formula and calculate as follows:
Volume (L) = 5.120 mol ÷ 6.750 M
Volume (L) = 0.7585 L
Therefore, the volume of the Li2SO3 solution is approximately 0.7585 liters.