Question

If the solubility of sodium chloride is 36 grams per 100 grams of water, which of the following solutions would be considered unsaturated? If the solubility of sodium chloride is 36 grams per 100 grams of water, which of the following solutions would be considered unsaturated? 3.25 moles of NaCl dissolved in 500 ml of water 1.85 moles of NaCl dissolved in 300 ml of water 5.8 moles of NaCl dissolved in 1 L of water none of the above

Answer 1

Answer: If the solubility of sodium chloride is 36 grams per 100 grams of water then 5.8 moles of NaCl dissolved in 1 L of water solution would be considered unsaturated.

Step-by-step explanation:

A solution which contains the maximum amount of solute is called a saturated solution. Whereas a solution in which more amount of solute is able to dissolve is called an unsaturated solution.

Now, the number of moles present in 36 g of NaCl (molar mass = 58.4 g/mol) is as follows.

`No. of moles = (mass)/(molar mass)\\= (36 g)/(58.4 g/mol)\\= 0.616 mol`

This shows that solubility of sodium chloride is 36 grams per 100 grams of water means a maximum of 0.616 mol of NaCl will dissolve in 100 mL of water.

So, a solution in which number of moles of NaCl are less than 0.616 mol per 100 mL then the solution formed will be an unsaturated solution.

• As 5.8 moles of NaCl dissolved in 1 L (or 1000 mL) of water. So, moles present in 100 mL are calculated as follows.

`Moles = (5.8 mol)/(1000 mL) * 100 mL\\= 0.58 mol`

• Moles present in 100 mL of water for 3.25 moles of NaCl dissolved in 500 ml in water are as follows.

`Moles = (3.25 mol)/(500 mL) * 100 mL\\0.65 mol`

• Moles present in 100 mL of water for 1.85 moles of NaCl dissolved in 300 ml of water are as follows.

`Moles = (1.85 mol)/(300 mL) * 100 mL\\= 0.616 mol`

Thus, we can conclude that if the solubility of sodium chloride is 36 grams per 100 grams of water then 5.8 moles of NaCl dissolved in 1 L of water solution would be considered unsaturated.