Question

the length of a rectangle is 2cm longer than its width. If the perimeter of the rectangle is 60 cm, find its length and width

Answer 1

Let the Width(W) = X cm

then the length(L)= (2+X)cm

Perimeter(P)= 60cm

P =L+W

L+W =P

(2+X)cm +X cm = 60 cm

2X+2=60

2X=60-2

2X=58

dividing both sides by 2

X=29cm

Width =X

Width =29cm

the width is 29cm

Length= (2+X)cm

= (2+29)cm

= 31cm

the length is 31cm

Answer 2

We will let w represent the width of the rectangle (in centimeters).

We know that the length is 2 cm longer than the width.

So the length is w + 2 .

We can label the rectangle as follows.

The perimeter is given as 60 cm.

So we solve for w as follows.

w + (w + 2) + w + (w + 2) = 60

w + w + 2 + w + w + 2 = 60

4w + 4 = 60

4w = 56

w = 14

Using this value of w, we can find w + 2.

w + 2 = 14 + 2 = 16

ANSWER

length: 16 cm

width: 14 cm