Answer:
![1.056](https://img.qammunity.org/2022/formulas/physics/college/azi3pidvqyi32am4pr4dv2bsbuwrdf4l9v.png)
Step-by-step explanation:
v = Velocity of sound = 342 m/s
= Velocity of source of sound = 9.3 m/s
= Frequency when car is approaching
= Frequency when car is moving away
= Frequecy of source of sound
The required ratio is
![(f_a)/(f_m)=((v)/(v-v_s)f_s)/((v)/(v+v_s)f_s)\\\Rightarrow (f_a)/(f_m)=(v+v_s)/(v-v_s)\\\Rightarrow (f_a)/(f_m)=(342+9.3)/(342-9.3)\\\Rightarrow (f_a)/(f_m)=1.056](https://img.qammunity.org/2022/formulas/physics/college/1y2kfaixwfbc6sox4pa9cx0t4qw2o1cwnt.png)
The ratio of the frequency you hear while the car is approaching to the frequency you hear while the car is moving away is
![1.056](https://img.qammunity.org/2022/formulas/physics/college/azi3pidvqyi32am4pr4dv2bsbuwrdf4l9v.png)