Question

In circle J with m \angle HJK= 50m∠HJK=50 and HJ=16HJ=16 units, find the length of arc HK. Round to the nearest hundredth.

Answer 1

13.96

Explanation:

length of an arc = theta/360 * 2πr

Given

m<HJK = 50

HJ = 16units

Required

length of arc HK

arc HK = 50/360 * 2(3.14)(16)

arc HK = 5/36 * 100.48

arc HK = 502.4/36

arcHK = 13.96

hence the length of arcHK to nearest hundredth is 13.96