Question

2. Before 0.5-kg ball is dropped from a third story window 20 m above the sidewalk. What is the potential

energy of the ball?
a. 4 J
b. 9800 J
C. 98 J
d. 150 J

Answer 1

(C). Pe=mgh
Pe=(.5kg)(10m/s^2)(20m)
Pe= 100J≈ 98J using 9.8 for G

Answer 2

C

Step-by-step explanation:

C

20*9.8*0.5

98