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Y=2x^2+12x+14 in vertex form

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Answer:

y = 2(x + 3)² - 4

Explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

Using the method of completing the square

y = 2x² + 12x + 14 ← factor out 2 from the first 2 terms

= 2(x² + 6x) + 14

To complete the square

add/subtract ( half the coefficient of the x- term)² to x² + 6x

y = 2(x² + 2(3)x + 9 - 9 ) + 14

= 2(x + 3)² - 18 + 14

= 2(x + 3)² - 4 ← in vertex form

User Mark Hills
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