Question

Let AABC be a right triangle with mzC = 90°. Given tan 2B = 0.125, find tan 2A.
tan ZA =

Answer 1

Solution given:

In right angled triangle ABC

TanB=
`(AC)/(BC)`

0.125×BC=AC

AC=0.125BC

now

TanA=
`(BC)/(AC)`=
`(BC)/(0.125BC)`=8° is your answer.

Answer 2

• 8

Explanation:

• tan = opposite leg / adjacent leg

Given

• tan ∠B = b/a = 0.125

Find tan ∠A

• tan ∠A = a/b = 1/ tan ∠B

Since tan ∠B = 0.125

• tan ∠A = 1/0.125 = 8