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Solve trigonometric function
cot0/tan0

2 Answers

12 votes


\\ \rm\Rrightarrow cotA/ tanA


\\ \rm\Rrightarrow (cosA)/(sinA)/ (sinA)/(cosA)


\\ \rm\Rrightarrow (cosA)/(sinA)* (cosA)/(sinA)


\\ \rm\Rrightarrow (cos^2A)/(sin^2A)


\\ \rm\Rrightarrow cot^2A

Note

  • theta is taken as A
User Faliorn
by
3.8k points
7 votes

Answer:


(1)/(\tan^2(\theta))}=\cot^2(\theta)

Explanation:


\cot(\theta)=(1)/(\tan(\theta))


\implies (\cot(\theta))/(\tan(\theta))=(1)/(\tan(\theta))/{\tan(\theta)}}=(1)/(\tan(\theta)) * (1)/(\tan(\theta)) =(1)/(\tan^2(\theta))}=\cot^2(\theta)

User Jason Tholstrup
by
3.8k points