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Fuel for an outboard motor has a gas to oil ratio of 50:1. How much oil is needed for 25.5L of gas?

User Benn
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1 Answer

4 votes

Answer:

The oil needed is 0.51.

Explanation:

Since you know that the gas to oil ratio is 50:1 and you have to find the oil needed for 25.5L of gas, you can write the numbers in the ratio as a fraction and let's consider that x is the amount of oil needed:


(50)/(1) = (25.5)/(x)

Now, you have to solve this using cross multiplication:

50*x=25.5*1

50x=25.5

Finally, your have to isolate the variable x:

x=25.5/50

x=0.51

According to this, the answer is that the oil needed is 0.51.

User Leni Kirilov
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