16.3k views
0 votes
Fuel for an outboard motor has a gas to oil ratio of 50:1. How much oil is needed for 25.5L of gas?

User Benn
by
7.9k points

1 Answer

4 votes

Answer:

The oil needed is 0.51.

Explanation:

Since you know that the gas to oil ratio is 50:1 and you have to find the oil needed for 25.5L of gas, you can write the numbers in the ratio as a fraction and let's consider that x is the amount of oil needed:


(50)/(1) = (25.5)/(x)

Now, you have to solve this using cross multiplication:

50*x=25.5*1

50x=25.5

Finally, your have to isolate the variable x:

x=25.5/50

x=0.51

According to this, the answer is that the oil needed is 0.51.

User Leni Kirilov
by
8.4k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.