Question

Answer this question 4 me please

Answer 1

Answer: C

Explanation:

To Ax^2+Bx+C=0 form (add 2 to both sides):

`2y^2-5y+2=0`

Use the quadratic formula (a = 2, b=-5, c= 2)

`y=(-\left(-5\right)\pm √(\left(-5\right)^2-4\cdot \:2\cdot \:2))/(2\cdot \:2)`

`y=(-\left(-5\right)\pm \:3)/(2\cdot \:2)`

`y=(-\left(-5\right)+3)/(2\cdot \:2),\:y_2=(-\left(-5\right)-3)/(2\cdot \:2)`

`y_(1)=2,\:\\y_(2)=(1)/(2)`