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Recursive formula for 3,5,7,9,11

User Carpenter
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1 Answer

5 votes

Answer:


a_(n) =
a_(n-1) + 2

Explanation:

There is a common difference d between consecutive terms

d = 5 - 3 = 7 - 5 = 9 - 7 = 11 - 9 = 2

A recursive formula allows a term in the sequence be found by adding d to the previous term, then


a_(n) =
a_(n-1) + 2 : with a₁ = 3

User Tbodt
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