Answer:
The probability of selecting two Democrats and three Republicans is 10.7%.
Explanation:
Given that a city council consists of seven Democrats and eight Republicans, if a committee of five people is selected, to find the probability of selecting two Democrats and three Republicans the following calculation must be performed:
7 = 100
2 = X
2 x 100/7 = X
28.57 = X
8 = 100
3 = X
3 x 100/8 = X
37.5 = X
0.2857 x 0.375 = X
0.107 = X
0.107 x 100 = 10.7
Therefore, the probability of selecting two Democrats and three Republicans is 10.7%.