Question

Si tengo 56 gramos de amoniaco gaseoso (NH3) ¿Cuántos moles y moléculas (entidades elementales) podré obtener?

Answer 1

Answer: 56 grams of gaseous ammonia (NH3), has 3.28 moles and
`19.80 * 10^(23)` molecules.

Step-by-step explanation:

Given: mass of
`NH_3` = 56 g

Molar mass of
`NH_3` is 17.03 g/mol.

As moles of a substance are its mass divided by the molar mass. Therefore, moles of
`NH_3` are calculated as follows.

`No. of moles = (mass)/(molar mass)\\= (56 g)/(17.03 g/mol)\\= 3.28 mol`

According to the mole concept, 1 mole of every substance contains
`6.022 * 10^(23)` molecules. Hence, number of molecules present in 3.28 moles of
`NH_3` are calculated as follows.

`No. of molecules = no. of moles * 6.022 * 10^(23)\\= 3.28 mol * 6.022 * 10^(23)\\= 19.80 * 10^(23)`

Therefore, we can conclude that 56 grams of gaseous ammonia (NH3), has 3.28 moles and
`19.80 * 10^(23)` molecules.