Question

(2c) Solve the equation: 6 = 1/2z

Answer 1

You move all terms to the left;

6-(1/2z)=0

Domain of the equation: 2z)!=0

z!=0/1

z!=0

You add all the numbers together, and all the variables;

-(+1/2z)+6=0

You get rid of parentheses;

-1/2z+6=0

You multiply all the terms by the denominator;

6*2z-1=0

You multiply elements;

12z-1=0

You move all terms containing z to the left, all other terms to the right;

12z=1

z=1/12

And your answer is: z=1/12

Explanation:

Answer 2

z=12

Explanation:

multiply both sides of the equation by 2

12=z

swap the sides of the equation

z=12