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What is the volume of 16.0 g of SO2 (g) at STP?
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What is the volume of 16.0 g of SO2 (g) at STP?

User Laffen
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1 Answer

5 votes

Answer:

Step-by-step explanation:

At STP 1 mole of an ideal gas = 22.4 L.

Assuming SO2 (sulfur dioxide) acts as an ideal as, we have 16 g SO2 x 1 mol/64 g = 0.25 moles SO2

0.25 moles x 22.4 L/mole = 5.6 liters

User Safi Habhab
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