Answer:
a. Substitution method.
b. Elimination method.
c. Graph method.
Explanation:
Given the following algebraic expressions;
a. y = 3x + 10 ....... equation 1
2x - 4y = -6 ...... equation 2
The above would be solved using substitution method.
Substituting eqn 1 into eqn 2, we have;
2x - 4(3x + 10) = -6
2x - 12x - 40 = -6
-10x = -6 + 40
-10x = 34
x = 34/10
x = 3.4
y = 3x + 10 = 3*3.4 + 10
y = 10.2 + 10 = 20.2
b. 9x + 2y = 29 ...... equation 1
3x - 2y = -17 ...... equation 2
The above would be solved using elimination method.
Adding eqn 1 to eqn 2, we have;
(9x + 3x) + (2y + (-2y)) = (29 + (-17))
12x + 0 = 12
12x = 12
x = 12/12 = 1
To find y, from eqn 1;
9(1) + 2y = 29
2y = 29 - 9
2y = 20
y = 20/2 = 10
c. y = 3/2x - 5
y = 2x + 8
The above would be solved using a graph method.
You choose a range for the value of y and x. These values are then plotted against each other and the slope of the graph is determined.