Question

A 0.530 M Ca(OH)2 solution was prepared by dissolving 36.0 grams of Ca(OH)2 in enough water. What is the total volume of the solution thus formed? (4 points)

Answer 1

0.917 liters

Hope this helps! :D

Step-by-step explanation:

5.

(08.02 MC)

A 0.530 M Ca(OH)2 solution was prepared by dissolving 36.0 grams of Ca(OH)2 in enough water. What is the total volume of the solution thus formed? (4 points)

Answer 2

0.917 L

Step-by-step explanation:

Step 1: Given data

• Molar concentration of the solution (M): 0.530 M (0.530 mol/L)

• Mass of Ca(OH)₂ (solute): 36.0 g

Step 2: Calculate the moles corresponding to 36.0 g of Ca(OH)₂

The molar mass of Ca(OH)₂ is 74.09 g/mol.

36.0 g × 1 mol/74.09 g = 0.486 mol

Step 3: Calculate the volume of the solution

Molarity is equal to the moles of solute divided by the liters of solution.

M = moles of solute / liters of solution

liters of solution = moles of solute / M

liters of solution = 0.486 mol / (0.530 mol/L) = 0.917 L