Question

the speed of light in a certain medium is 0.6c. find critical angle , if the index of refraction is 1.67​

Answer 1

`\theta_c = 36.78^o`

Step-by-step explanation:

The relationship between the refractive index and the critical angle is given as follows:

`\eta = (1)/(Sin\ \theta_c) \\\\Sin\ \theta_c = (1)/(\eta)\\\\\theta_c = Sin^(-1)((1)/(\eta) )`

where,

η = refractive index = 1.67

θc = critical angle =?

Therefore,

`\theta_c = Sin^(-1)((1)/(1.67) )`

`\theta_c = 36.78^o`