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Please help I have a lot of other due assignments and I don’t have Time and paper thx:)

Please help I have a lot of other due assignments and I don’t have Time and paper-example-1
User Vsoni
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1 Answer

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Median: 69

First Quartile: 65.5

Third Quartile: 73

Interquartile Range: 7.5

Explanation:

First, put all of the numbers in order.

63, 64, 67, 68, 70, 72, 74, 76.

Median

For the median, it is the center of the data set.

To find the median of this data set, add 68, and 70, then divide by 2.

The Median is 69.

First Quartile

To find the first quartile, find the range below the median (63-68).

Find the median of that range.

Add 64 & 67 together, then divide by 2.

The first quartile = 65.5

Third Quartile

Do the same as the first quartile, but do it with the range above the median (70-76).

Add 72 & 74 together, then divide by 2.

The third quartile = 73.

Interquartile Range

Now, take the first and third quartile, and subtract.


73-65.5=IR


7.5 = IR

The interquartile range is 7.5.

User Atul Stha
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