Question

The eye of the Atlantic giant squid has a diameter of 3.50 × 10^2 mm. If the eye

is viewed in a concave mirror with a radius of curvature equal to the diameter
of the eye and the eye is 0.800 × 10^3 mm from the mirror, how far is the image
from the mirror? What is the size of the image? Is the image real or virtual?​

Answer 1

q = 224 mm, h ’= - 98 mm, real imagen

Step-by-step explanation:

For this exercise let's use the constructor equation

`(1)/(f) = (1)/(p) + (1)/(q)`

where f is the focal length, p and q are the distance to the object and the image respectively.

In a mirror the focal length is

f = R / 2

indicate us radius of curvature is equal to the diameter of the eye

R = 3,50 10² mm

f = 3.50 10² /2 = 1.75 10² mm

they also say that the distance to the object is p = 0.800 10³ mm

1 / q = 1 / f - 1 / p

1 / q = 1 / 175 - 1 /800

1 / q = 0.004464

q = 224 mm

to calculate the size let's use the magnification ratio

m =
`(h')/(h) = - (q)/(p)`

h '=
`- (q)/(p) \ h`

h ’= - 224 350 / 800

h ’= - 98 mm

in concave mirrors the image is real.