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A line has a slope of m = 3/4 and goes through the point (16, -2). Which of these is the equation of the line?

User Yibe
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1 Answer

3 votes

Answer:

y = (3/4)*x - 14

Explanation:

The slope-point general equation of the straight line is:

y = m*x + b

In that equation, m is the slope and b is the intercept with y-axis

The equation has two parameters to determine m and b. for a different pair of values we get just one unique straight line equation. To do that we need two conditions.

Here we have m = 3/4 and the point P ( 16 , -2), by substitution

y = (3/4)*x + b and

- 2 = (3/4)*16 + b - 2 = 3*4 +b -2 = 12 +b b = -14

Then the final equation is:

y = (3/4)*x - 14

User Greyson Parrelli
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