Answer:
51.2feet
Explanation:
Given;
Horizontal distance = 40feet (Adjacent)
Angle of elevation = 52 degrees
Required
Height of the pole H (Opposite)
Using the SOH CAH TOA identity
Tan theta = opp/adj
Tan 52 = H/40
H = 40tan 52
H = 40(1.2799)
H = 51.2 feet
Hence height, h, of the flagpole to the nearest tenth is 51.2feet