Question

Write the standard form of the equation of the circles that passes through (0, 3) with its center at (0,0)

Answer 1

`x^2+y^2=9`

Explanation:

Equation of a circle (when centred at the origin):

`x^2+y^2=r^2` where r is the radius of the circle

Plug in the point (0,3) to solve for the radius squared

`0^2+3^2=r^2\\9=r^2`

Plug r² back into the original equation

`x^2+y^2=9`

I hope this helps!