Question

In the reaction to prepare chlorine gas,4.35g of manganese dioxide (MnO2) reacted with concentrated hydrochloric acid (HCI) according to the following equation:

MnO2 + 4HCI = MnCL2 + 2H2O + Cl2
i) how many moles of manganese dioxide were there in the 4.35 g sample?
ii) how many moles of hydrochloric acid were required to reacy with 4.35g of manganese dioxide.
iii) Calculate the maximum number of water molecules that could be produced.
iv) how many atoms of hydrigen did this number of water molecules contain?

Answer 1

molecule after the george by a number ones open this helps ahhaah

Answer 2

mncL2 is the water molecule