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How many moles of potassium Chlorate are needed to produce 15.0 moles of oxygen

User Comintern
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Answer:

10 moles of potassium Chlorate are required to produce 15 mole of oxygen

Step-by-step explanation:

The balanced chemical equation is

2KClO3(s)→2KCl(s)+3O2(g)

2 moles of potassium Chlorate produce 3 moles of oxygen

Number of moles of potassium Chlorate required to produce 1 mole of oxygen
= (2)/(3)

Number of moles of potassium Chlorate required to produce 15 mole of oxygen


= (2)/(3) * 15\\= 10

10 moles of potassium Chlorate are required to produce 15 mole of oxygen

User Spadar Shut
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