Question

How many grams of nitrogen in 7.3 x 10^24 molecules of NaNO3

Answer 1

To calculate the number of grams of nitrogen in 7.3 x 10²⁴ molecules of NaNO3, we need to find the molar mass of NaNO3 and calculate the number of moles of nitrogen. The molar mass of NaNO3 is 84.00 g/mol and the number of moles of nitrogen is 12.13 mol. Therefore, the mass of nitrogen is 170.16 grams.

Step-by-step explanation:

To determine the number of grams of nitrogen in 7.3 x 10²⁴ molecules of NaNO3, we need to find the molar mass of NaNO3 and calculate the number of moles of nitrogen. The molar mass of NaNO3 is equal to the sum of the atomic masses of sodium (Na), nitrogen (N), and oxygen (O).:

Molar mass of NaNO3 = 22.99 g/mol (Na) + 14.01 g/mol (N) + 3(16.00 g/mol) (O)

= 22.99 g/mol + 14.01 g/mol + 48.00 g/mol

= 84.00 g/mol

Next, we calculate the number of moles of nitrogen in 7.3 x 10²⁴ molecules of NaNO3:

Number of moles of nitrogen = (7.3 x 10²⁴ molecules)(1 mol/6.022 x 10²³ molecules)

= 12.13 mol

Finally, we can calculate the mass of nitrogen:

Mass of nitrogen = (number of moles of nitrogen)(molar mass of nitrogen)

= (12.13 mol)(14.01 g/mol)

= 170.16 g

Answer 2

Step-by-step explanation:

Convert molecules to moles:

1 mole of NaNO₃= 6.02 x 10^23 molecules of NaNO₃

7.3 x10^24/(6.02 x 10^23)=12mol NaNO₃

Find molar mass:

NaNO₃=1 mole of Na and 1mole of N and 3mole of O

Find grams:

14.01g x 12= 168.12 g of N