Question

Please help with #2 and #3

Answer 1

2.
`V_2=17L`

3.
`V=82.9L`

Step-by-step explanation:

Hello there!

2. In this case, we can evidence the problem by which volume and temperature are involved, so the Charles' law is applied to:

`(V_2)/(T_2)=(V_1)/(T_1)`

Thus, considering the temperatures in kelvins and solving for the final volume, V2, we obtain:

`V_2=(V_1T_2)/(T_1)`

Therefore, we plug in the given data to obtain:

`V_2=(18.2L(22+273)K)/((45+273)K) \\\\V_2=17L`

3. In this case, it is possible to realize that the 3.7 moles of neon gas are at 273 K and 1 atm according to the STP conditions; in such a way, considering the ideal gas law (PV=nRT), we can solve for the volume as shown below:

`V=(nRT)/(P)`

Therefore, we plug in the data to obtain:

`V=(3.7mol*0.08206(atm*L)/(mol*K)*273.15K)/(1atm)\\\\V=82.9L`

Best regards!