Answer:
0.0312
Explanation:
Given :
Mean or average time, xbar = 12.25
Standard deviation, s = 3
Sample size, n = 500
The test statistic :
(x - xbar) ÷ (s/sqrt(n))
(12 - 12.25) ÷ 3/sqrt(500)
-0.25 ÷ 0.1341640
Test statistic = - 1.863
The Pvalue :
P(Z < - 1.863) = 1 - P(Z ≤ 1.863)
P(Z < - 1.863) = 0.0312
Hence, the Pvalue = 0.0312