How does A(x) = 4^x change over the interval from x = 2 to x = 3?

Ofir Attal asked Feb 25, 2023

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Ofir Attal asked Feb 25, 2023

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24 votes

Replace x and solve:

4^2 = 16

4^3 = 64

Now divide the solutions

64/16 = 4

This is an increase of a factor of 4.

ANSWER:

H(x) increases by a factor of 4

Craigo answered Mar 1, 2023

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