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How does A(x) = 4^x change over the interval from x = 2 to x = 3?

How does A(x) = 4^x change over the interval from x = 2 to x = 3?-example-1
User Ofir Attal
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1 Answer

24 votes
24 votes

Replace x and solve:


4^2 = 16

4^3 = 64

Now divide the solutions

64/16 = 4


This is an increase of a factor of 4.


ANSWER:

H(x) increases by a factor of 4

User Craigo
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2.9k points