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Find a line that is perpendicular to y = 2/5x-1 that goes through (3,6)

1 Answer

5 votes

Answer:


\sf y=-(5)/(2)x+(27)/(2)

Explanation:

given equation:


\sf y = (2)/(5) x -1

using the formula: y = mx + b

Here, we can determine 2/5 is the slope

if perpendicular: -1/m → -1/2/5 → -5/2

using the formula:


\sf y - y1 = m ( x - x1)


\sf y - 6 = -(5)/(2) ( x - 3 )


\sf y - 6 = -(5)/(2) x - (15)/(2)


\sf y = -(5)/(2) x + (15)/(2) +6


\sf y=-(5)/(2)x+(27)/(2)

User Steve Kehlet
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