Hello.
In order to solve the equation, we need to isolate x.
First, subtract 1 from both sides:
![\mathrm{7x+1-1=8x+3-1}](https://img.qammunity.org/2023/formulas/mathematics/high-school/28kniehm3h600bav2jnvwdhvtnq8zf89p0.png)
![\mathrm{7x=8x+2}](https://img.qammunity.org/2023/formulas/mathematics/high-school/jy000o2grxhv4p0jbp0g6hm1fbza269oog.png)
Now, subtract 8x from both sides:
![\mathrm{7x-8x=8x-8x+2}](https://img.qammunity.org/2023/formulas/mathematics/high-school/rdt01k3zmxfssb3mbo45fv33vwvs6kfegg.png)
![\mathrm{7x-8x=2}](https://img.qammunity.org/2023/formulas/mathematics/high-school/33i0xt2c55497kcfxllu3domz4g30236uh.png)
![\mathrm{-x=2}](https://img.qammunity.org/2023/formulas/mathematics/high-school/8rte2h05cuvm36zhl0csfascvnnqp5ivyz.png)
Now, the minus sign is the same as -1.
In order to isolate x, we need to multiply both sides by -1:
![\mathrm{x=-2}](https://img.qammunity.org/2023/formulas/mathematics/high-school/mbt69ecyeyl7d034ce2644sx6wzxdamjup.png)
Therefore, the answer is
![\mathrm{x=-2}](https://img.qammunity.org/2023/formulas/mathematics/high-school/mbt69ecyeyl7d034ce2644sx6wzxdamjup.png)
I hope it helps.
Have a nice day.
![\boxed{imperturbability}](https://img.qammunity.org/2023/formulas/mathematics/high-school/4e5twsd8myuuptqybbee35e90dbwcl3efm.png)