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Write (3i-2/3)-(6i-5) as a complex number in standard form.

A.(13/3-9i)
B.(13/3-3i)
C.(17/3-3i)
D.(13/3+9i)
E.13 - i

User Andrew Liu
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1 Answer

4 votes

Answer:

(13/3+9i)

Explanation:

User Jenilyn
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