What is the value of A when we rewrite (32/5)^-2x as A^x

Question

asked Oct 2, 2022 215k views

2 Answers

Vladimir Arustamian · Answer 1 · 2022-10-06T21:37:50+0000

Answer:

((25)/(1024))^x

Explanation:

The given expression is :

((32)/(5))^(-2x)

We need to rewrite it in the form of
A^x .

We know that,
((1)/(x))^(-a)=x^a

So,

$((32)/(5))^(-2x)=((5)/(32))^(2x)\\\\=((5^2)/(32^2))^x\\\\=((25)/(1024))^x$

So,
A=(25)/(1024) . Hence, this is the required solution.