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What is the value of A when we rewrite (32/5)^-2x as A^x​

2 Answers

1 vote

Answer: A = (32/5)^-2

Explanation:

User Longhua
by
5.7k points
4 votes

Answer:


((25)/(1024))^x

Explanation:

The given expression is :


((32)/(5))^(-2x)

We need to rewrite it in the form of
A^x.

We know that,
((1)/(x))^(-a)=x^a

So,


((32)/(5))^(-2x)=((5)/(32))^(2x)\\\\=((5^2)/(32^2))^x\\\\=((25)/(1024))^x

So,
A=(25)/(1024). Hence, this is the required solution.