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Special right triangles. find the value of x?

hypotenuse = leg ×

√(2)


Special right triangles. find the value of x? hypotenuse = leg × √(2) ​-example-1

1 Answer

1 vote

Answer:

x = (9√2)/2

Explanation:

Reference angle = 45°

Hypotenuse length = 9

Adjacent length = x

Apply the trigonometric ratio CAH:

Cos 45° = Adj/Hyp

Cos 45° = x/9

Multiply both sides by 9

9*Cos 45 = x

9*1/√2 = x (cos 45 = 1/√2)

9/√2 = x

Rationalize

(9*√2)/2 = x

x = (9√2)/2

User Shaheen Zahedi
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